Represent $3 . \overline{42}$ on the number line, using successive magnification, up to $4$ decimal places.
The number obtained on rationalizing the denominator of $\frac{1}{7-\sqrt{2}}$ is
Subtract $: 0 . \overline{52}-0.4 \overline{6}$
Simplify the following:
$3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$
If $\sqrt{5}=2.236,$ then evaluate $\frac{4-\sqrt{5}}{\sqrt{5}}$ correct to four decimal places.
For each question, select the proper option from four options given, to make the statement true : (Final answer only)
$0 . \overline{3}=\ldots \ldots . .$