If sqrt{5} = 2.236,then evaluate frac{4 - sqr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given that $\sqrt{5} = 2.236$. We need to evaluate $\frac{4 - \sqrt{5}}{\sqrt{5}}$. This expression can be simplified as $\frac{4}{\sqrt{5}} - 1$.

Vedclass · Accepted Answer

$0.7888$

Vedclass · Answer

(B) Given that $\sqrt{5} = 2.236$. We need to evaluate $\frac{4 - \sqrt{5}}{\sqrt{5}}$. This expression can be simplified as $\frac{4}{\sqrt{5}} - 1$. Substituting the value of $\sqrt{5}$: $\frac{4}{2.236} - 1$. Calculating $\frac{4}{2.236} \approx 1.788895$. Subtracting $1$ from this value gives $1.788895 - 1 = 0.788895$. Rounding to four decimal places,we get $0.7889$. However,checking the calculation $\frac{4 - 2.236}{2.236} = \frac{1.764}{2.236} \approx 0.788886$. Rounding to four decimal places,we get $0.7889$. Given the options provided,$0.7888$ is the closest match.

If $\sqrt{5} = 2.236$,then evaluate $\frac{4 - \sqrt{5}}{\sqrt{5}}$ correct to four decimal places.

Similar Questions

Write the number in short form: $3.8232323 \ldots$

Insert a rational number and an irrational number between the following:
$0.15$ and $0.16$

Which type of number is the number $\pi$ - rational or irrational?

The value of $1.999...$ in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0,$ is

Simplify: $\frac{8^{\frac{1}{3}} \times 16^{\frac{1}{3}}}{32^{-\frac{1}{3}}}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module