Rationalise the denominator of the following:
$\frac{2}{3 \sqrt{3}}$
$\frac{2 \sqrt{5}}{7}$
$\frac{6 \sqrt{7}}{9}$
$\frac{5 \sqrt{3}}{9}$
$\frac{2 \sqrt{3}}{9}$
Construct the square root spiral up to $\sqrt{6}$.
Find five rational numbers between $-\frac{3}{4}$ and $-\frac{1}{3}$
The number obtained on rationalizing the denominator of $\frac{1}{7-\sqrt{2}}$ is
Simplify the following:
$4 \sqrt{28} \div 3 \sqrt{7}$
Which of the following is irrational?