Rationalise the denominator of $\frac{1}{7+3 \sqrt{2}}$
Rationalise the denominator of $\frac{1}{7+3 \sqrt{2}}$
$\frac{1}{7+3 \sqrt{2}}=\frac{1}{7+3 \sqrt{2}} \times\left(\frac{7-3 \sqrt{2}}{7-3 \sqrt{2}}\right)=\frac{7-3 \sqrt{2}}{49-18}=\frac{7-3 \sqrt{2}}{31}$
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