Rationalise the denominator of $\frac{5}{\sqrt{3}-\sqrt{5}}$.
Rationalise the denominator of $\frac{5}{\sqrt{3}-\sqrt{5}}$.
Here we use the Identity $(iii)$ given earlier.
So, $\frac{5}{\sqrt{3}-\sqrt{5}}=\frac{5}{\sqrt{3}-\sqrt{5}} \times \frac{\sqrt{3}+\sqrt{5}}{\sqrt{3}+\sqrt{5}}=\frac{5(\sqrt{3}+\sqrt{5})}{3-5}=\left(\frac{-5}{2}\right)(\sqrt{3}+\sqrt{5})$
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