Rationalise the denominator of frac{5}{sqrt{3 | vedclass

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Question

(B) To rationalise the denominator,we multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{3}+\sqrt{5})$.$\

Vedclass · Accepted Answer

$-\frac{5}{2}(\sqrt{3}+\sqrt{5})$

Vedclass · Answer

(B) To rationalise the denominator,we multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{3}+\sqrt{5})$.$\frac{5}{\sqrt{3}-\sqrt{5}} = \frac{5}{\sqrt{3}-\sqrt{5}} 	imes \frac{\sqrt{3}+\sqrt{5}}{\sqrt{3}+\sqrt{5}}$Using the algebraic identity $(a-b)(a+b) = a^2 - b^2$ in the denominator:$= \frac{5(\sqrt{3}+\sqrt{5})}{(\sqrt{3})^2 - (\sqrt{5})^2}$$= \frac{5(\sqrt{3}+\sqrt{5})}{3 - 5}$$= \frac{5(\sqrt{3}+\sqrt{5})}{-2}$$= -\frac{5}{2}(\sqrt{3}+\sqrt{5})$

Rationalise the denominator of $\frac{5}{\sqrt{3}-\sqrt{5}}$.

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