Let a_1, a_2, a_3, ldots. be a GP of increasi | vedclass

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Question

$a_4 \cdot a_6=9 \Rightarrow\left(a_5\right)^2=9 \Rightarrow a_5=3$

$a_5+a_7=24 \Rightarrow a_5+a_5 r^2=24 \Rightarrow\left(1+r^2\right)=8 \Rightar

Vedclass · Accepted Answer

$60$

Vedclass · Answer

$a_4 \cdot a_6=9 \Rightarrow\left(a_5\right)^2=9 \Rightarrow a_5=3$

$a_5+a_7=24 \Rightarrow a_5+a_5 r^2=24 \Rightarrow\left(1+r^2\right)=8 \Rightarrow r=\sqrt{7}$ $\Rightarrow a=\frac{3}{49}$

$\Rightarrow a_1 a_9+a_2 a_4 a_9+a_5+a_7=9+27+3+21=60$

Let $a_1, a_2, a_3, \ldots$. be a $GP$ of increasing positive numbers. If the product of fourth and sixth terms is $9$ and the sum of fifth and seventh terms is $24 ,$ then $a_1 a_9+a_2 a_4 a_9+a_5+a_7$ is equal to $.........$.

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