Find the sum to $n$ terms of the sequence, $8,88,888,8888 \ldots$
The given sequence is $8,88,888,8888 \ldots$
This sequence is not a $G.P.$ However, it can be changed to $G.P.$ by writing the terms as
$S_{n}=8+88+888+8888+\ldots \ldots$ to $n$ terms
$=\frac{8}{9}[9+99+999+9999+\ldots \ldots . . $ to $ n $ terms $]$
$=\frac{8}{9}[(10+10^{2}+\ldots \ldots . n \text { terms })$
$-(1+1+1+\ldots . . n \text { terms })]$
$=\frac{8}{9}\left[\frac{10\left(10^{n}-1\right)}{10-1}-n\right]$
$=\frac{8}{9}\left[\frac{10\left(10^{n}-1\right)}{9}-n\right]$
$=\frac{80}{81}\left(10^{n}-1\right)-\frac{8}{9} n$
If the sum of three terms of $G.P.$ is $19$ and product is $216$, then the common ratio of the series is
If ${x_r} = \cos (\pi /{3^r}) - i\sin (\pi /{3^r}),$ (where $i = \sqrt{-1}),$ then value of $x_1.x_2.x_3......\infty ,$ is :-
An $A.P.$, a $G.P.$ and a $H.P.$ have the same first and last terms and the same odd number of terms. The middle terms of the three series are in
In an increasing geometric progression ol positive terms, the sum of the second and sixth terms is $\frac{70}{3}$ and the product of the third and fifth terms is $49$. Then the sum of the $4^{\text {th }}, 6^{\text {th }}$ and $8^{\text {th }}$ terms is :-
Find the sum of the following series up to n terms:
$5+55+555+\ldots$