In the nuclear reaction: X(n, alpha) {_3Li^7} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given nuclear reaction is $X(n, \alpha) {_3Li^7}$.This can be written as: $_ZX^A + _0n^1 	o _3Li^7 + _2He^4$.According to the law of conserva

Vedclass · Accepted Answer

$_5B^{10}$

Vedclass · Answer

(A) The given nuclear reaction is $X(n, \alpha) {_3Li^7}$.This can be written as: $_ZX^A + _0n^1 	o _3Li^7 + _2He^4$.According to the law of conservation of mass number and atomic number:For atomic number $(Z)$: $Z + 0 = 3 + 2 \implies Z = 5$.For mass number $(A)$: $A + 1 = 7 + 4 \implies A + 1 = 11 \implies A = 10$.Thus,the nucleus $X$ is $_5X^{10}$,which corresponds to Boron-$10$ $(_{5}B^{10})$.

In the nuclear reaction: $X(n, \alpha) {_3Li^7}$,the term $X$ will be

Similar Questions

For a nucleus to be stable,the correct relation between neutron number $N$ and proton number $Z$ is

Is nuclear force short range or long range?

Express unified atomic mass unit $(amu)$ in $kg$.

Nuclear forces are

$A$ nucleus has mass number $\alpha$ and radius $R_{\alpha}$. Another nucleus has mass number $\beta$ and radius $R_{\beta}$. If $\beta = 8\alpha$,then $R_{\alpha}/R_{\beta}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module