A nucleus of lead $Pb _{82}^{214}$ emits two electrons followed by an $\alpha$-particle. The resulting nucleus will have

  • [KVPY 2011]
  • A

    $82$ protons and $128$ neutrons

  • B

    $80$ protons and $130$ neutrons

  • C

    $82$ protons and $130$ neutrons

  • D

    $78$ protons and $134$ neutrons

Similar Questions

Consider the following nuclear reactions:

$I$. ${ }_{7}^{14} N +{ }_{2}^{4} He \longrightarrow{ }_{8}^{17} O + X$

$II$. ${ }_{4}^{9} Be +{ }_{2}^{4} H \longrightarrow{ }_{6}^{12} He +Y$

Then,

  • [KVPY 2017]

An element $A$ decays into element $C$ by a two step process :

$A \to B + {\;_2}H{e^4}$

$B \to C + \;2{e^ - }$

Then

  • [AIPMT 1989]

During a negative beta decay

  • [IIT 1987]

Beta rays emitted by a radioactive material are

$\alpha$ -particle consists of 

  • [NEET 2019]