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(D) In a radioactive decay process, if the atomic number $(Z)$ and the mass number $(A)$ of the nucleus remain unchanged, it implies that the nucleus

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Photon

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(D) In a radioactive decay process, if the atomic number $(Z)$ and the mass number $(A)$ of the nucleus remain unchanged, it implies that the nucleus has transitioned from a higher energy state to a lower energy state without changing its composition.This process is known as gamma $(\gamma)$ decay.During gamma decay, the nucleus emits a high-energy electromagnetic radiation called a photon.Since a photon has zero rest mass and zero charge, its emission does not alter the atomic number or the mass number of the parent nucleus.Therefore, the correct option is $(d)$.

In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following would be emitted in the decay process?

Similar Questions

In the given nuclear reaction,the element $X$ is:
${ }_{11}^{22} Na \rightarrow X + e ^{+} + \nu$

When a nucleus with atomic number $Z$ and mass number $A$ undergoes a radioactive decay process:

$A$ radioactive nucleus $_{92}X^{235}$ decays to $_{91}Y^{231}$. Which of the following particles are emitted?

The decay constant of the end product of a radioactive series is

$A$ nuclear reaction is given by ${}_{Z}X^{A} \to {}_{Z+1}Y^{A} + {}_{-1}e^{0} + \bar{\nu}$,which represents:

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