In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following would be emitted in the decay process
Proton
Neutron
Electron
Photon
On the bombardment of neutron with Boron. $\alpha$-particle is emitted and product nuclei formed is
The isotope ${ }_5^{12} \mathrm{~B}$ having a mass $12.014 \mathrm{u}$ undergoes $\beta$-decay to ${ }_6^{12} \mathrm{C} .{ }_6^{12 .}$ has an excited state of the nucleus $\left({ }_6^{12} \mathrm{C}^*\right)$ at $4.041 \mathrm{MeV}$ above its ground state. If ${ }_5^{12} \mathrm{~F}$ decays to ${ }_6^{12} \mathrm{C}^*$, the maximum kinetic energy of the $\beta$-particle in units of $\mathrm{MeV}$ is ( $1 \mathrm{u}=931.5 \mathrm{MeV} / c^2$, where $c$ is the speed of light in vacuum).
In the given nuclear reaction, the element $X$ is :
${ }_{11}^{22} Na \rightarrow X + e ^{+}+v$
The $\alpha$-particle is the nucleus of an atom of
A nucleus of an element ${}_{84}{X^{202}}$ emits an $\alpha $-particle first, $\beta $ -particle next and then a gamma photon. The final nucleus formed has an atomic number