Which one of the following is a possible nuclear reaction
Which one of the following is a possible nuclear reaction
- [AIIMS 2006]
- A
${}_5^{10}B + {}_2^4He \longrightarrow {}_7^{13}N + {}_1^1H$
- B
${}_{11}^{23}Na + {}_1^1H \longrightarrow {}_{10}^{20}Ne + {}_2^4He$
- C
${}_{93}^{239}Np \longrightarrow {}_{94}^{239}Pu + {\beta ^ - } + \bar v$
- D
${}_7^{11}N + {}_1^1H \longrightarrow {}_6^{12}C + {\beta ^ - } + v$
Similar Questions
Explain $\beta -$ decay and how does a radioactive nucleus emit $\beta -$ particles, even if there are no $\beta -$ particles in the nucleus ? Here why does radioactive nuclide not change during beta emission ?
Explain $\beta -$ decay and how does a radioactive nucleus emit $\beta -$ particles, even if there are no $\beta -$ particles in the nucleus ? Here why does radioactive nuclide not change during beta emission ?
In gamma ray emission from a nucleus
In gamma ray emission from a nucleus
- [AIEEE 2007]
In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following would be emitted in the decay process
In a radioactive decay, neither the atomic number nor the mass number changes. Which of the following would be emitted in the decay process
During negative $\beta$-decay
During negative $\beta$-decay
The isotope ${ }_5^{12} \mathrm{~B}$ having a mass $12.014 \mathrm{u}$ undergoes $\beta$-decay to ${ }_6^{12} \mathrm{C} .{ }_6^{12 .}$ has an excited state of the nucleus $\left({ }_6^{12} \mathrm{C}^*\right)$ at $4.041 \mathrm{MeV}$ above its ground state. If ${ }_5^{12} \mathrm{~F}$ decays to ${ }_6^{12} \mathrm{C}^*$, the maximum kinetic energy of the $\beta$-particle in units of $\mathrm{MeV}$ is ( $1 \mathrm{u}=931.5 \mathrm{MeV} / c^2$, where $c$ is the speed of light in vacuum).
The isotope ${ }_5^{12} \mathrm{~B}$ having a mass $12.014 \mathrm{u}$ undergoes $\beta$-decay to ${ }_6^{12} \mathrm{C} .{ }_6^{12 .}$ has an excited state of the nucleus $\left({ }_6^{12} \mathrm{C}^*\right)$ at $4.041 \mathrm{MeV}$ above its ground state. If ${ }_5^{12} \mathrm{~F}$ decays to ${ }_6^{12} \mathrm{C}^*$, the maximum kinetic energy of the $\beta$-particle in units of $\mathrm{MeV}$ is ( $1 \mathrm{u}=931.5 \mathrm{MeV} / c^2$, where $c$ is the speed of light in vacuum).
- [IIT 2016]