What is the respective number of $\alpha $ and $\beta $ particles emitted in the following radioactive decay
$_{90}{X^{200}}{ \to _{80}}{Y^{168}}$
$6 \,and\,8$
$8 \,and\,8$
$6 \,and\,6$
$8 \,and\, 6$
Consider the following radioactive decay process
${ }_{84}^{218} A \stackrel{\alpha}{\longrightarrow} A_1 \stackrel{\beta^{-}}{\longrightarrow} A_2 \stackrel{\gamma}{\longrightarrow} A_3 \stackrel{\alpha}{\longrightarrow} A_4 \stackrel{B^{+}}{\longrightarrow} A_5 \stackrel{\gamma}{\longrightarrow} A_6$
The mass number and the atomic number $A _6$ are given by
Neutrino is a particle, which is
In the given reaction $_z{X^A}{ \to _{z + 1}}{Y^A}{ \to _{z - 1}}{K^{A - 4}}{ \to _{z - 1}}{K^{A - 4}}$ Radioactive radiations are emitted in the sequence
In the disintegration series
$_{92}^{238}U\xrightarrow{\alpha }x\xrightarrow{\beta }_Z^AY$
The value of $Z$ and $A$ respectively will be
Which of the following processes represents a gamma-decay