After one alpha and two beta emissions,what h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) An $\alpha$ decay involves the emission of a helium nucleus $(_{2}^{4}He)$,which decreases the mass number $(A)$ by $4$ and the atomic number $(Z)

Vedclass · Accepted Answer

Mass number reduces by $4$

Vedclass · Answer

(B) An $\alpha$ decay involves the emission of a helium nucleus $(_{2}^{4}He)$,which decreases the mass number $(A)$ by $4$ and the atomic number $(Z)$ by $2$. $A$ $\beta$ decay involves the emission of an electron $(_{-1}^{0}e)$,which leaves the mass number $(A)$ unchanged and increases the atomic number $(Z)$ by $1$. Starting with a nucleus $_{Z}^{A}X$: $1$. After one $\alpha$ emission: $_{Z-2}^{A-4}Y$. $2$. After two $\beta$ emissions: $_{Z-2+2}^{A-4}X = _{Z}^{A-4}X$. Thus,the mass number reduces by $4$ and the atomic number remains unchanged.

After one $\alpha$ and two $\beta$ emissions,what happens to the nucleus?

Similar Questions

$A$ nucleus with mass number $184$ initially at rest emits an $\alpha$-particle. If the $Q$ value of the reaction is $5.5\, \text{MeV}$,calculate the kinetic energy of the $\alpha$-particle in $\text{MeV}$.

In a radioactive reaction $_{92}X^{232} \to _{82}Y^{204}$,the number of $\alpha$-particles emitted is:

In the nuclear decay sequence given below:
$_Z{X^A} \to {}_{Z + 1}{Y^A} \to {}_{Z - 1}{K^{A - 4}} \to {}_{Z - 1}{K^{A - 4}}$
the particles emitted in the sequence are:

Which of the following is not emitted during the radioactive decay of a radioactive element?

The nucleus ${ }_{88}^{226} Ra$ is converted into ${ }_{82}^{206} Pb$ by the emission of alpha $(\alpha)$ and beta $(\beta)$ particles. The number of alpha and beta particles emitted are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module