In the formula bar{x} = A + frac{Sigma f_{i} | vedclass

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(C) The given formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} 	imes c$ is the step-deviation method used to calculate the mean of grou

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class length

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(C) The given formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} 	imes c$ is the step-deviation method used to calculate the mean of grouped data.In this formula:- $\bar{x}$ is the mean.- $A$ is the assumed mean.- $f_{i}$ is the frequency of the $i^{th}$ class.- $u_{i} = \frac{x_{i} - A}{c}$,where $x_{i}$ is the class mark.- $c$ represents the class length (or class size),which is the difference between the upper limit and the lower limit of a class interval.

Marks	Number of students
Below $10$	$3$
Below $20$	$12$
Below $30$	$27$
Below $40$	$57$
Below $50$	$75$
Below $60$	$80$

Class	$10-30$	$30-50$	$50-70$	$70-90$	$90-110$
Frequency	$17$	$f_{1}$	$32$	$f_{2}$	$19$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$,$c$ represents .......

Similar Questions

For the following distribution,the modal class is:

Marks Number of students

Below $10$ $3$

Below $20$ $12$

Below $30$ $27$

Below $40$ $57$

Below $50$ $75$

Below $60$ $80$

The mode of the observations $4, 5, 6, 3, 4, 3, 3, 2, 3, 5$ is $\ldots \ldots \ldots \ldots .$

The mean of the following frequency distribution is $60$ and the total frequency is $120$. Find the missing frequencies $f_{1}$ and $f_{2}$.

Class $10-30$ $30-50$ $50-70$ $70-90$ $90-110$

Frequency $17$ $f_{1}$ $32$ $f_{2}$ $19$

The mean of $15$ observations is $16$. If $2$ is added to each observation and then each result is divided by $3$,the new mean is:

Find the median of the following frequency distribution:

Class $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ $65-70$ $70-75$

Frequency $1$ $2$ $5$ $10$ $17$ $15$ $9$ $5$ $3$

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