The mean of $15$ observations is $16$. If $2$ is added to each observation and then each result is divided by $3$,the new mean is:
- A$20 \frac{2}{3}$
- B$21 \frac{1}{3}$
- C$23$
- D$6$
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Similar Questions
Consider the following distribution:
Marks obtained Number of students More than or equal to $0$ $63$ More than or equal to $10$ $58$ More than or equal to $20$ $55$ More than or equal to $30$ $51$ More than or equal to $40$ $48$ More than or equal to $50$ $42$
The frequency of the class $30-40$ is:
| Marks obtained | Number of students |
| More than or equal to $0$ | $63$ |
| More than or equal to $10$ | $58$ |
| More than or equal to $20$ | $55$ |
| More than or equal to $30$ | $51$ |
| More than or equal to $40$ | $48$ |
| More than or equal to $50$ | $42$ |
The frequency of the class $30-40$ is:
Easy
View SolutionFor the calculation of mode of the following frequency distribution,$f_{1} = \dots \dots \dots \dots \dots \dots$
Class $0-100$ $100-200$ $200-300$ $300-400$ $400-500$ $500-600$ Frequency $12$ $18$ $27$ $20$ $17$ $6$
| Class | $0-100$ | $100-200$ | $200-300$ | $300-400$ | $400-500$ | $500-600$ |
| Frequency | $12$ | $18$ | $27$ | $20$ | $17$ | $6$ |
Easy
View Solution$\frac{Z-M}{M-\bar{x}}=\ldots \ldots \ldots \ldots$
Easy
View SolutionThe two types of Ogives drawn for a frequency distribution intersect at point $(20, 25)$. Then,the median of the data is .......
Easy
View SolutionIf $Z=12$ and $M=16,$ then $\bar{x}=$ ............
Medium
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