Find the median of the following frequency di | vedclass

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(C) To find the median,we first calculate the cumulative frequency $(cf)$:  ClassFrequency $(f)$Cumulative Frequency $(cf)$  $30-35$$1$$1$  $35-40$$2$

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$54.56$

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(C) To find the median,we first calculate the cumulative frequency $(cf)$:  ClassFrequency $(f)$Cumulative Frequency $(cf)$  $30-35$$1$$1$  $35-40$$2$$3$  $40-45$$5$$8$  $45-50$$10$$18$  $50-55$$17$$35$  $55-60$$15$$50$  $60-65$$9$$59$  $65-70$$5$$64$  $70-75$$3$$67$Total frequency $N = 67$. So,$N/2 = 67/2 = 33.5$.Looking at the $cf$ column,the median class is $50-55$ because $33.5$ lies in this interval.Here,lower limit $l = 50$,class size $h = 5$,frequency of median class $f = 17$,and cumulative frequency of the class preceding the median class $cf = 18$.Using the median formula: $	ext{Median} = l + \left( \frac{N/2 - cf}{f} ight) 	imes h$$	ext{Median} = 50 + \left( \frac{33.5 - 18}{17} ight) 	imes 5$$	ext{Median} = 50 + \left( \frac{15.5}{17} ight) 	imes 5$$	ext{Median} = 50 + \frac{77.5}{17} \approx 50 + 4.5588 \approx 54.56$.

Find the median of the following frequency distribution:

Class $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ $65-70$ $70-75$

Frequency $1$ $2$ $5$ $10$ $17$ $15$ $9$ $5$ $3$

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Find the median of the following frequency distribution: Class $30-35$ $35-40$ $40-45$ $45-50$ $50-55$ $55-60$ $60-65$ $65-70$ $70-75$ Frequency $1$ $2$ $5$ $10$ $17$ $15$ $9$ $5$ $3$