Three $\alpha - $ particles and one $\beta - $ particle decaying takes place in series from an isotope $_{88}R{a^{238}}$. Finally the isotope obtained will be
Three $\alpha - $ particles and one $\beta - $ particle decaying takes place in series from an isotope $_{88}R{a^{238}}$. Finally the isotope obtained will be
- A
$_{84}{X^{220}}$
- B
$_{86}{X^{222}}$
- C
$_{83}{X^{224}}$
- D
$_{83}{X^{215}}$
Similar Questions
$_{86}{A^{222}}{ \to _{84}}{B^{210}}$. In this reaction how many $\alpha $ and $\beta $ particles are emitted
$_{86}{A^{222}}{ \to _{84}}{B^{210}}$. In this reaction how many $\alpha $ and $\beta $ particles are emitted
In which of the following decay, the element does not change
In which of the following decay, the element does not change
Before the neutrino hypothesis, the beta decay process was thought to be the transition, $n \to p + {e^ - }$ If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.
Before the neutrino hypothesis, the beta decay process was thought to be the transition, $n \to p + {e^ - }$ If this was true, show that if the neutron was at rest, the proton and electron would emerge with fixed energies and calculate them. Experimentally, the electron energy was found to have a large range.
Alpha particles are
Alpha particles are
- [AIPMT 1999]
Assertion : Cobalt $-60$ is useful in cancer therapy.
Reason : Cobalt $-60$ is a source of $\gamma - $ radiations capable of killing cancerous cells
Assertion : Cobalt $-60$ is useful in cancer therapy.
Reason : Cobalt $-60$ is a source of $\gamma - $ radiations capable of killing cancerous cells
- [AIIMS 2006]