Three $\alpha - $ particles and one $\beta - $ particle decaying takes place in series from an isotope $_{88}R{a^{238}}$. Finally the isotope obtained will be
Three $\alpha - $ particles and one $\beta - $ particle decaying takes place in series from an isotope $_{88}R{a^{238}}$. Finally the isotope obtained will be
- A
$_{84}{X^{220}}$
- B
$_{86}{X^{222}}$
- C
$_{83}{X^{224}}$
- D
$_{83}{X^{215}}$
Similar Questions
In a radioactive decay chain, the initial nucleus is ${}_{90}^{232}Th$. At the end there are $6\,\,\alpha -$ particles and $4\,\,\beta -$ particles with are emitted. If the end nucleus is ${}_Z^AX\,,\,A$ and $Z$ are given by
In a radioactive decay chain, the initial nucleus is ${}_{90}^{232}Th$. At the end there are $6\,\,\alpha -$ particles and $4\,\,\beta -$ particles with are emitted. If the end nucleus is ${}_Z^AX\,,\,A$ and $Z$ are given by
- [JEE MAIN 2019]
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A nucleus $_Z^AX$ emits an $\alpha$- particle. The resultant nucleus emits a ${\beta ^ + }$ particle. The respective atomic and mass no. of the final nucleus will be
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- [AIIMS 2006]