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(A) The initial nucleus is $_{72}A^{180}$.$1$. After $\alpha$-decay ($_{2}He^{4}$ emission): Mass number decreases by $4$,atomic number decreases by $

Vedclass · Accepted Answer

$172$ and $69$

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(A) The initial nucleus is $_{72}A^{180}$.$1$. After $\alpha$-decay ($_{2}He^{4}$ emission): Mass number decreases by $4$,atomic number decreases by $2$.$_{72}A^{180} \xrightarrow{\alpha} _{70}A_1^{176}$$2$. After $\beta$-decay (electron emission): Mass number remains unchanged,atomic number increases by $1$.$_{70}A_1^{176} \xrightarrow{\beta} _{71}A_2^{176}$$3$. After $\alpha$-decay: Mass number decreases by $4$,atomic number decreases by $2$.$_{71}A_2^{176} \xrightarrow{\alpha} _{69}A_3^{172}$$4$. After $\gamma$-decay: Neither mass number nor atomic number changes.$_{69}A_3^{172} \xrightarrow{\gamma} _{69}A_4^{172}$Thus,the mass number is $172$ and the atomic number is $69$.

$A$ radioactive nucleus undergoes a series of decays according to the scheme:
$A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\alpha} A_3 \xrightarrow{\gamma} A_4$
If the mass number and atomic number of $A$ are $180$ and $72$ respectively,what are these numbers for $A_4$?

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$A$ radioactive nucleus undergoes a series of decays according to the scheme:$A \xrightarrow{\alpha} A_1 \xrightarrow{\beta} A_2 \xrightarrow{\alpha} A_3 \xrightarrow{\gamma} A_4$If the mass number and atomic number of $A$ are $180$ and $72$ respectively,what are these numbers for $A_4$?