In the figure a capacitor is filled with dielectrics. The resultant capacitance is
In the figure a capacitor is filled with dielectrics. The resultant capacitance is
- A
$\frac{{2{\varepsilon _0}A}}{d}\,\left[ {\frac{1}{{{k_1}}} + \frac{1}{{{k_2}}} + \frac{1}{{{k_3}}}} \right]$
- B
$\frac{{{\varepsilon _0}A}}{d}\,\left[ {\frac{1}{{{k_1}}} + \frac{1}{{{k_2}}} + \frac{1}{{{k_3}}}} \right]$
- C
$\frac{{2{\varepsilon _0}A}}{d}\,\left[ {{k_1} + {k_2} + {k_3}} \right]$
- D
None of these
Similar Questions
Assertion : The electrostatic force between the plates of a charged isolated capacitor decreases when dielectric fills whole space between plates.
Reason : The electric field between the plates of a charged isolated capacitance increases when dielectric fills whole space between plates.
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Reason : The electric field between the plates of a charged isolated capacitance increases when dielectric fills whole space between plates.
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