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(B) When an insulator (dielectric) plate enters the capacitor,the capacitance $C$ increases because $C = \frac{K \epsilon_0 A}{d}$.Since the capacitor

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First flows clockwise then anticlockwise

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(B) When an insulator (dielectric) plate enters the capacitor,the capacitance $C$ increases because $C = \frac{K \epsilon_0 A}{d}$.Since the capacitor is connected to a battery,the potential difference $V$ remains constant.The charge on the capacitor $Q = CV$ increases as the plate enters.This increase in charge requires a current to flow from the battery to the capacitor plates,which corresponds to a charging current in the external circuit.Inside the capacitor,the displacement current $I_d$ is equal to the conduction current in the external circuit,so it flows in the direction that supports the charging process (clockwise).As the insulator plate leaves the capacitor,the capacitance $C$ decreases,causing the charge $Q$ on the capacitor to decrease.This results in a discharge current flowing out of the capacitor,meaning the displacement current now flows in the opposite direction (anticlockwise).Therefore,the displacement current first flows clockwise and then anticlockwise.

An insulator plate is passed between the plates of a capacitor. Then the displacement current

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