In a hostel,60 % of the students read Hindi n | vedclass

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Question

(A) Let $H$ be the event that a student reads Hindi newspaper and $E$ be the event that a student reads English newspaper. Given: $P(H) = 60/100 = 3/5

Vedclass · Accepted Answer

$1/3$

Vedclass · Answer

(A) Let $H$ be the event that a student reads Hindi newspaper and $E$ be the event that a student reads English newspaper. Given: $P(H) = 60/100 = 3/5$,$P(E) = 40/100 = 2/5$,and $P(H \cap E) = 20/100 = 1/5$. We need to find the conditional probability $P(E | H)$,which is the probability that a student reads English newspaper given that she reads Hindi newspaper. Using the formula for conditional probability: $P(E | H) = \frac{P(E \cap H)}{P(H)}$ Substituting the values: $P(E | H) = \frac{1/5}{3/5} = \frac{1}{3}$

In a hostel,$60 \%$ of the students read Hindi newspaper,$40 \%$ read English newspaper and $20 \%$ read both Hindi and English newspapers. $A$ student is selected at random. If she reads Hindi newspaper,find the probability that she reads English newspaper.

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