In odot( O , 12), minor widehat{ ACB } subten | vedclass

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Question

Here, $r=12$ and $	heta=30$.

Length of major $\widehat{ ADB }=2 \pi r-\frac{\pi r 	heta}{180}$

$=2 \pi(12)-\frac{\pi 	imes 12 	imes 30}{180}

Vedclass · Accepted Answer

$22\pi $

Vedclass · Answer

Here, $r=12$ and $	heta=30$.

Length of major $\widehat{ ADB }=2 \pi r-\frac{\pi r 	heta}{180}$

$=2 \pi(12)-\frac{\pi 	imes 12 	imes 30}{180}=24 \pi-2 \pi=22 \pi \,cm$

In $\odot( O , 12)$, minor $\widehat{ ACB }$ subtends an angle of measure $30$ at the centre. Then. the length of major $\widehat{A D B}$ is $\ldots \ldots \ldots . . cm .$

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