The length of the minute hand of a clock is 6 | vedclass

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Question

(C) The length of the minute hand represents the radius of the circle,so $r = 6 \, cm$.In $60 \, 	ext{minutes}$,the minute hand sweeps an angle of $3

Vedclass · Accepted Answer

$18.84$

Vedclass · Answer

(C) The length of the minute hand represents the radius of the circle,so $r = 6 \, cm$.In $60 \, 	ext{minutes}$,the minute hand sweeps an angle of $360^{\circ}$.Therefore,in $10 \, 	ext{minutes}$,the angle swept by the minute hand is $	heta = \frac{360^{\circ}}{60} 	imes 10 = 60^{\circ}$.The area of the region swept is the area of a sector with radius $r = 6 \, cm$ and central angle $	heta = 60^{\circ}$.$	ext{Area} = \frac{	heta}{360^{\circ}} 	imes \pi r^2 = \frac{60^{\circ}}{360^{\circ}} 	imes 3.14 	imes 6 	imes 6$.$	ext{Area} = \frac{1}{6} 	imes 3.14 	imes 36 = 3.14 	imes 6 = 18.84 \, cm^2$.

The length of the minute hand of a clock is $6 \, cm$. The area of the region swept by it in $10 \, \text{minutes}$ is $\ldots \ldots \ldots \ldots \, cm^2$. $(\pi = 3.14)$

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