In $Fig.$ a square of diagonal $8\, cm$ is inscribed in a circle. Find the area of the shaded region.

1061-34

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Let the side of a square be a and the radius of circle be $r$.

Given that, length of diagonal of square $=8\, cm$

$\Rightarrow$ $a \sqrt{2}=8$

$\Rightarrow$ $a=4 \sqrt{2} \, cm$

Now, Diagonal of a square $=$ Diameter of a circle

$\Rightarrow$ Diameter of circle $=8$

$\Rightarrow$ Radius of circle $=r=\frac{\text { Diameter }}{2}$

$\Rightarrow$ $r=\frac{8}{2}=4 \,cm$

$\therefore$ Area of circle $=\pi r^{2}=\pi(4)^{2}$

$=16 \pi \times\, cm ^{2}$

and Area of square $=a^{2}=(4 \sqrt{2})^{2}$

$=32 cm ^{2}$

So, the area of the shaded region $=$ Area of circle $-$ Area of square

$=(16 \pi-32) \, cm ^{2}$

Hence, the required area of the shaded region is $(16 \pi-32) \, cm ^{2}$.

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