Floor of a room is of dimensions 5 ,m times 4 | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Given, floor of a room is covered with circular tiles.

Length of a floor of a room $(l)=5\, m$

and breadth of floor of a room $(b)=4\, m$

$

Vedclass · Accepted Answer

$4.3$

Vedclass · Answer

Given, floor of a room is covered with circular tiles.

Length of a floor of a room $(l)=5\, m$

and breadth of floor of a room $(b)=4\, m$

$	herefore$ Area of floor of a room $=l 	imes b$

$=5 	imes 4=20\, m ^{2}$

Diameter of each circular tile $=50\, cm$

$\Rightarrow$ Radius of each circular tile $=\frac{50}{2}=25 \,cm$

$=\frac{25}{100}\,m =\frac{1}{4}\, m$ [$\because$ diameter $=2 	imes$ radius $]$

Now, area of a circular tile $=\pi$ (radius)$^{2}$

$=3.14 	imes\left(\frac{1}{4}ight)^{2}=\frac{3.14}{16}\, m ^{2}$

$	herefore$ Area of $80$ circular tiles $=80 	imes \frac{3.14}{16}=5 	imes 3.14=15.7\,m ^{2}$ $[\because 80$ congruent circular tiles covering the floor of a room]

So, area of floor that remains uncovered with tiles $=$ Area of floor of a room $-$ Area of $80$ circular tiles

$=20-157=4.3 \,m ^{2}$

Hence, the required area of floor that remains uncovered with tiles is $4.3 m ^{2}$.

Floor of a room is of dimensions $5 \,m \times 4 \,m$ and it is covered with circular tiles of diameters $50 \,cm$ each as shown in $Fig.$ Find the area of floor that remains uncovered with tiles. (Use $\pi=3.14)$ (in $m ^{2}$)

Similar Questions

Three circles each of radius $3.5\, cm$ are drawn in such a way that each of them touches the other two. Find the area enclosed between these circles. (in $cm ^{2}$)

The area of $\odot( O , r)$ is $240\,cm ^{2} .$ In $\odot( O , r),$ minor $\widehat{ ACB }$ subtends an angle of measure $45$ at the centre. Then, the area of minor sector $OACB$ is $\ldots \ldots \ldots . . cm ^{2}$.

In $Fig.$ arcs have been drawn of radius $21\, cm$ each with vertices $A , B , C$ and $D$ of quadrilateral $A B C D$ as centres. Find the area of the shaded region. (in $cm ^{2}$)

The areas of two sectors of two different circles with equal corresponding arc lengths are equal. Is this statement true? Why?

In $Fig.$ a circle is inscribed in a square of side $5 \,cm$ and another circle is circumscribing the square. Is it true to say that area of the outer circle is two times the area of the inner circle? Give reasons for your answer.