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Question

Let the radius of a circle be $r$.

$	herefore$ Circumference of a circle $=2 \pi r$

Let the radii of two circles are $r_{1}$ and $r_{2}$ whose

Vedclass · Accepted Answer

$33$

Vedclass · Answer

Let the radius of a circle be $r$.

$	herefore$ Circumference of a circle $=2 \pi r$

Let the radii of two circles are $r_{1}$ and $r_{2}$ whose values are $15 \,cm$ and $18 \,cm$ respectively.

i.e. $\quad r_{1}=15$ cm and $r_{2}=18 \, cm$

Now, by given condition, Circumference of circle $=$ Circumference of first circle $+$ Circumference of second circle

$\Rightarrow$  $2 \pi r=2 \pi r_{1}+2 \pi r_{2}$

$\Rightarrow$ $r = r _{1}+ r _{2}$

$\Rightarrow$ $r=15+18$

$r=33 \,cm$

Hence, required radius of a circle is $33 \,cm$.

Find the radius of a circle whose circumference is equal to the sum of the circumferences of two circles of radii $15 \,cm$ and $18 \,cm$ (in $cm$)

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