If the sum of the areas of two circles with radii $R_{1}$ and $R_{2}$ is equal to the area of a circle of radius $R$, then
If the sum of the areas of two circles with radii $R_{1}$ and $R_{2}$ is equal to the area of a circle of radius $R$, then
- A
$R _{1}+ R _{2}= R$
- B
$R _{1}+ R _{2} < R$
- C
$R _{1}^{2}+ R _{2}^{2}= R ^{2}$
- D
$R _{1}^{2}+ R _{2}^{2}< R ^{2}$
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