If the perimeter of a circle is equal to that of a square, then the ratio of their areas is
$22: 7$
$7: 22$
$14: 11$
$11: 14$
The length of the minute hand of a clock is $14 \,cm .$ If the minute hand moves from $1$ to $10$ on the dial, then $\ldots \ldots \ldots \ldots cm ^{2}$ area will be covered.
Which of the following correctly matches the information given in Part $I$ and Part $II$ ?
Part $I$ | Part $II$ |
$1.$ Formula to find the length of a minor arc | $a.$ $C=2\pi r$ |
$2.$ Formula to find the area of a minor sector | $b.$ $A =\pi r^{2}$ |
$3.$ Formula to find the area of a circle | $c.$ $l=\frac{\pi r \theta}{180}$ |
$4.$ Formula to find the circumference of a circle | $d.$ $A=\frac{\pi r^{2} \theta}{360}$ |
The closed figure formed by an arc of a circle and the radii through its end points is called .........
$\widehat{ ACB }$ is a minor arc of $\odot( O , 8 \,cm ) .$ If $m \angle AOB =45,$ the length of minor $\widehat{ ACB }$ is $\ldots \ldots \ldots . . cm .$
In $\odot( O , r),$ the length of minor $\widehat{ ACB }$ is one-eighth of the circumference of the circle. Then, the measure of the angle subtended at the centre by that arc is $\ldots \ldots \ldots \ldots$