If the matrix begin{bmatrix} 1 & 3 & lambda + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) matrix is singular if its determinant is equal to $0$.Given the matrix $A = \begin{bmatrix} 1 & 3 & \lambda + 2 \ 2 & 4 & 8 \ 3 & 5 & 10 \end{bm

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) matrix is singular if its determinant is equal to $0$.Given the matrix $A = \begin{bmatrix} 1 & 3 & \lambda + 2 \ 2 & 4 & 8 \ 3 & 5 & 10 \end{bmatrix}$.Setting the determinant $|A| = 0$:$|A| = 1(4 	imes 10 - 8 	imes 5) - 3(2 	imes 10 - 8 	imes 3) + (\lambda + 2)(2 	imes 5 - 4 	imes 3) = 0$$|A| = 1(40 - 40) - 3(20 - 24) + (\lambda + 2)(10 - 12) = 0$$|A| = 1(0) - 3(-4) + (\lambda + 2)(-2) = 0$$0 + 12 - 2(\lambda + 2) = 0$$12 - 2\lambda - 4 = 0$$8 - 2\lambda = 0$$2\lambda = 8$$\lambda = 4$.

If the matrix $\begin{bmatrix} 1 & 3 & \lambda + 2 \\ 2 & 4 & 8 \\ 3 & 5 & 10 \end{bmatrix}$ is singular,then $\lambda = $

Similar Questions

If $\omega$ is the cube root of unity,then $\left| \begin{array}{ccc} 1 & \omega & \omega^2 \\ \omega & \omega^2 & 1 \\ \omega^2 & 1 & \omega \end{array} \right| = $

If $-9$ is a root of the equation $\left| \begin{array}{ccc} x & 3 & 7 \\ 2 & x & 2 \\ 7 & 6 & x \end{array} \right| = 0$,then the other two roots are:

Find the area of the triangle whose vertices are $(3,8), (-4,2)$ and $(5,1)$.

Let $A = \begin{bmatrix} 3-t & 1 & 0 \\ -1 & 3-t & 1 \\ 0 & -1 & 0 \end{bmatrix}$ and $\det(A) = 5$,then find the value of $t$.

Evaluate the determinant: $\left| \begin{array}{ccc} 1 & a & b \\ -a & 1 & c \\ -b & -c & 1 \end{array} \right|$

Vedclass Test Series

Exam Paper Generator

Online Exam Module