If the line frac{x}{a} + frac{y}{b} = 1 passe | vedclass

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(D) Given the line equation $\frac{x}{a} + \frac{y}{b} = 1$. Since the line passes through $(2, -3)$,we have $\frac{2}{a} - \frac{3}{b} = 1$  --- $(1)

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$(-1, -1)$

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(D) Given the line equation $\frac{x}{a} + \frac{y}{b} = 1$. Since the line passes through $(2, -3)$,we have $\frac{2}{a} - \frac{3}{b} = 1$  --- $(1)$. Since the line passes through $(4, -5)$,we have $\frac{4}{a} - \frac{5}{b} = 1$  --- $(2)$. Let $X = \frac{1}{a}$ and $Y = \frac{1}{b}$. The equations become $2X - 3Y = 1$ and $4X - 5Y = 1$. Multiplying the first equation by $2$,we get $4X - 6Y = 2$. Subtracting this from the second equation: $(4X - 5Y) - (4X - 6Y) = 1 - 2$,which gives $Y = -1$. Substituting $Y = -1$ into $2X - 3Y = 1$: $2X - 3(-1) = 1 \implies 2X + 3 = 1 \implies 2X = -2 \implies X = -1$. Thus,$\frac{1}{a} = -1 \implies a = -1$ and $\frac{1}{b} = -1 \implies b = -1$. Therefore,$(a, b) = (-1, -1)$.

If the line $\frac{x}{a} + \frac{y}{b} = 1$ passes through the points $(2, -3)$ and $(4, -5)$,then $(a, b) = $

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