The equation of the straight line which is perpendicular to $y = x$ and passes through $(3, 2)$ is

Points $A$ and $B$ are in the first quadrant; point $O$ is the origin. If the slope of $OA$ is $1$,the slope of $OB$ is $7$,and $OA = OB = r$,then the slope of $AB$ is:

The minimum area of the triangle formed by the variable line $3 \cos \theta \cdot x + 4 \sin \theta \cdot y = 12$ and the coordinate axes is

Find the slope of the line passing through the points $(3, -2)$ and $(3, 4)$.

Find the equation of the line passing through the point $(1, 2)$ and perpendicular to the line $y = 3x - 1$.

Find the equation of the line passing through $(-3, 5)$ and perpendicular to the line passing through the points $(2, 5)$ and $(-3, 6)$.