The Fahrenheit temperature F and absolute tem | vedclass

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(A) Assuming $F$ along the $x$-axis and $K$ along the $y$-axis,we have two points $(32, 273)$ and $(212, 373)$ in the $XY$-plane.By the two-point form

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$-459.4$

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(A) Assuming $F$ along the $x$-axis and $K$ along the $y$-axis,we have two points $(32, 273)$ and $(212, 373)$ in the $XY$-plane.By the two-point form,the point $(F, K)$ satisfies the equation:$K - 273 = \frac{373 - 273}{212 - 32}(F - 32)$$K - 273 = \frac{100}{180}(F - 32)$$K - 273 = \frac{5}{9}(F - 32)$$K = \frac{5}{9}(F - 32) + 273$ ... $(1)$When $K = 0$,Equation $(1)$ gives:$0 = \frac{5}{9}(F - 32) + 273$$-\frac{5}{9}(F - 32) = 273$$F - 32 = -\frac{273 	imes 9}{5}$$F - 32 = -491.4$$F = -491.4 + 32 = -459.4$

The Fahrenheit temperature $F$ and absolute temperature $K$ satisfy a linear equation. Given that $K=273$ when $F=32$ and that $K=373$ when $F=212$. Express $K$ in terms of $F$ and find the value of $F$,when $K =0$.

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