If one end of the diameter of the circle x^2+ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given equation of the circle is $x^2+y^2-4x-6y+11=0$.Comparing this with the general form $x^2+y^2+2gx+2fy+c=0$,we get $2g=-4 \Rightarrow g=-2

Vedclass · Accepted Answer

$(1,2)$

Vedclass · Answer

(C) The given equation of the circle is $x^2+y^2-4x-6y+11=0$.Comparing this with the general form $x^2+y^2+2gx+2fy+c=0$,we get $2g=-4 \Rightarrow g=-2$ and $2f=-6 \Rightarrow f=-3$.The center of the circle is $(-g, -f) = (2, 3)$.Let the other end of the diameter be $(h, k)$.Since the center of the circle is the midpoint of the diameter,we have:$\frac{h+3}{2} = 2$ $\Rightarrow h+3 = 4$ $\Rightarrow h = 1$$\frac{k+4}{2} = 3$ $\Rightarrow k+4 = 6$ $\Rightarrow k = 2$Thus,the other end of the diameter is $(1, 2)$.

If one end of the diameter of the circle $x^2+y^2-4x-6y+11=0$ is $(3,4)$,then the other end of the diameter is

Similar Questions

The number of tangents which can be drawn from the point $(-1, 2)$ to the circle $x^2 + y^2 + 2x - 4y + 4 = 0$ is

In a circle of diameter $40 \, cm$,the length of a chord is $20 \, cm$. Find the length of the minor arc of the chord.

If a circle passes through the points $(0,0), (x,0),$ and $(0,y)$,then the coordinates of its centre are

$S_1$ and $S_2$ are two concentric circles of radii $1$ and $2$ respectively. Two parallel tangents to $S_1$ cut off an arc from $S_2$. The length of the arc is

The radius of the circle whose arc of length $15 \ cm$ makes an angle of $3/4$ radian at the centre is ..... $cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module