(D) The equation of the circle is $x^2 + y^2 + 2x - 4y + 4 = 0$.Let the point be $P(-1, 2)$.To check the position of the point with respect to the cir

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(D) The equation of the circle is $x^2 + y^2 + 2x - 4y + 4 = 0$.Let the point be $P(-1, 2)$.To check the position of the point with respect to the circle,we calculate the power of the point $S_1$ by substituting the coordinates into the circle equation:$S_1 = (-1)^2 + (2)^2 + 2(-1) - 4(2) + 4$$S_1 = 1 + 4 - 2 - 8 + 4 = -1$.Since $S_1 Therefore,no tangent can be drawn from this point to the circle.

Class 11 Mathematics 10-1.Circle and System of Circles Geometrical problems regarding circle and its properties

Medium

The number of tangents which can be drawn from the point $(-1, 2)$ to the circle $x^2 + y^2 + 2x - 4y + 4 = 0$ is

A
$1$
B
$2$
C
$3$
D
$0$

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10-1.Circle and System of Circles

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Geometrical problems regarding circle and its properties

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The number of tangents which can be drawn from the point $(-1, 2)$ to the circle $x^2 + y^2 + 2x - 4y + 4 = 0$ is

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