If $x=\alpha, y=\beta, z=\gamma$ is the unique solution of the system of linear equations $2x-3y+5z=12$,$5x+2y+3z=11$,and $x+2y-3z=-3$,then $2\alpha+5\beta+3\gamma=$

  • A
    $10$
  • B
    $11$
  • C
    $3$
  • D
    $2$

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