જો $z = \frac{(2-i)(1+i)^3}{(1-i)^2}$ હોય,તો $\operatorname{Arg}(z) = $
- A$\tan^{-1}\left(\frac{1}{3}\right) - \pi$
- B$\tan^{-1}\left(\frac{3}{4}\right) - \pi$
- C$\pi - \tan^{-1}\left(\frac{3}{4}\right)$
- D$\tan^{-1}\left(\frac{1}{3}\right)$
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