If cos theta = - frac{1}{{sqrt 2 }} and tan t | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $\cos 	heta = - \frac{1}{{\sqrt 2 }} \Rightarrow 	heta = \frac{{3\pi }}{4},\,\frac{{5\pi }}{4}$; 

$	an 	heta = 1 \Rightarrow 	heta =

Vedclass · Accepted Answer

$(2n + 1)\,\pi + \frac{\pi }{4}$

Vedclass · Answer

(b) $\cos 	heta = - \frac{1}{{\sqrt 2 }} \Rightarrow 	heta = \frac{{3\pi }}{4},\,\frac{{5\pi }}{4}$; 

$	an 	heta = 1 \Rightarrow 	heta = \frac{\pi }{4},\,\frac{{5\pi }}{4}$

$	herefore $ The general value is $2n\pi + \frac{{5\pi }}{4}$ or $(2n + 1)\pi + \frac{\pi }{4}$.

If $\cos \theta = - \frac{1}{{\sqrt 2 }}$ and $\tan \theta = 1$, then the general value of $\theta $ is

Similar Questions

If $2(\sin x - \cos 2x) - \sin 2x(1 + 2\sin x)2\cos x = 0$ then

Number of solutions of $8cosx$ = $x$ will be

If $5\cos 2\theta + 2{\cos ^2}\frac{\theta }{2} + 1 = 0, - \pi < \theta < \pi $, then $\theta = $

The number of solutions $x$ of the equation $\sin \left(x+x^2\right)-\sin \left(x^2\right)=\sin x$ in the interval $[2,3]$ is

Let $S=\left\{\theta \in[-\pi, \pi]-\left\{\pm \frac{\pi}{2}\right\}: \sin \theta \tan \theta+\tan \theta=\sin 2 \theta\right\} \text {. }$ If $T =\sum_{\theta \in S } \cos 2 \theta$, then $T + n ( S )$ is equal