If $2(\sin x - \cos 2x) - \sin 2x(1 + 2\sin x)2\cos x = 0$ then
If $2(\sin x - \cos 2x) - \sin 2x(1 + 2\sin x)2\cos x = 0$ then
- A
$x = \frac{\pi }{6}(4n + 1)$or $x = \frac{\pi }{2}(4n - 1)$
- B
$x = \frac{\pi }{6}(4n - 1)$or $x = \frac{\pi }{2}(4n - 1)$
- C
$x = \frac{\pi }{6}(4n + 1)$or $x = \frac{\pi }{2}(4n + 1)$
- D
None of these
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