If 2{sin ^2}theta = 3cos theta , where 0 le t | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $2 - 2{\cos ^2}	heta = 3\cos 	heta $

==> $2{\cos ^2} + 3\cos 	heta - 2 = 0$

==> $\cos 	heta = \frac{{ - 3 \pm \sqrt {9 + 16} }}{4}

Vedclass · Accepted Answer

$\frac{\pi }{3},\frac{{5\pi }}{3}$

Vedclass · Answer

(b) $2 - 2{\cos ^2}	heta = 3\cos 	heta $

==> $2{\cos ^2} + 3\cos 	heta - 2 = 0$

==> $\cos 	heta = \frac{{ - 3 \pm \sqrt {9 + 16} }}{4} = \frac{{ - 3 \pm 5}}{4}$

Neglecting $(-)$ sign, we get

$\cos 	heta = \frac{1}{2} = \cos \left( {\frac{\pi }{3}} ight)$

$ \Rightarrow $ $	heta = 2n\pi \pm \frac{\pi }{3}$.

The values of $	heta $ between $0$ and $2\pi $ are $\frac{\pi }{3},{m{ }}\frac{{{m{5}}\pi }}{{m{3}}}$.

If $2{\sin ^2}\theta = 3\cos \theta ,$ where $0 \le \theta \le 2\pi $, then $\theta = $

Similar Questions

Number of principal solution of the equation $tan \,3x - tan \,2x - tan\, x = 0$, is

The equation $2{\cos ^2}\left( {\frac{x}{2}} \right)\,{\sin ^2}x\, = \,{x^2}\, + \,\frac{1}{{{x^2}}},\,0\,\, \leqslant \,\,x\,\, \leqslant \,\,\frac{\pi }{2}\,\,$ has

The number of values of $x$ for which $sin2x + sin4x = 2$ is

If $\sin \theta + \cos \theta = \sqrt 2 \cos \alpha $, then the general value of $\theta $ is

The angles $\alpha, \beta, \gamma$ of a triangle satisfy the equations $2 \sin \alpha+3 \cos \beta=3 \sqrt{2}$ and $3 \sin \beta+2 \cos \alpha=1$. Then, angle $\gamma$ equals