If tan theta + tan 2theta + tan 3theta = tan | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) $	an 	heta + 	an 2	heta + 	an 3	heta = 	an 	heta 	an 2	heta 	an 3	heta $

$	an 6	heta = \frac{{	an 	heta + 	an 2	heta + 	an 3

Vedclass · Accepted Answer

$\frac{{n\pi }}{6}$

Vedclass · Answer

(b) $	an 	heta + 	an 2	heta + 	an 3	heta = 	an 	heta 	an 2	heta 	an 3	heta $

$	an 6	heta = \frac{{	an 	heta + 	an 2	heta + 	an 3	heta - 	an 	heta 	an 2	heta 	an 3	heta }}{{1 - \sum 	an 	heta 	an 2	heta }}$

$= 0, $ (from the given condition)

$ \Rightarrow $ $6	heta = n\pi \Rightarrow 	heta = n\pi /6$.

Trick : In such type of problems, the general value of $	heta $ is given by $\frac{{n\pi }}{{{m{sum \,of\, number\, of\, }}	heta }}$.

So the general value of $	heta $ is $\frac{{n\pi }}{{1 + 2 + 3}} = \frac{{n\pi }}{6}$.

If $\tan \theta + \tan 2\theta + \tan 3\theta = \tan \theta \tan 2\theta \tan 3\theta $, then the general value of $\theta $ is

Similar Questions

The equation $2{\cos ^2}\left( {\frac{x}{2}} \right)\,{\sin ^2}x\, = \,{x^2}\, + \,\frac{1}{{{x^2}}},\,0\,\, \leqslant \,\,x\,\, \leqslant \,\,\frac{\pi }{2}\,\,$ has

Find the principal solutions of the equation $\sin x=\frac{\sqrt{3}}{2}$

If the solution for $\theta $ of $\cos p\theta + \cos q\theta = 0,\;p > 0,\;q > 0$ are in $A.P.$, then the numerically smallest common difference of $A.P.$ is

Find the solution of $\sin x=-\frac{\sqrt{3}}{2}$

If $\cos {40^o} = x$ and $\cos \theta = 1 - 2{x^2}$, then the possible values of $\theta $ lying between ${0^o}$ and ${360^o}$is