If cos theta + sec theta = frac{5}{2}, then t | vedclass

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Question

(d) ${\cos ^2}	heta - \frac{5}{2}\cos 	heta + 1 = 0$

$ \Rightarrow $ $\cos 	heta = \frac{{(5/2) \pm \sqrt {(25/4) - 4} }}{2} = \frac{{5 \pm 3}}{

Vedclass · Accepted Answer

$2n\pi \pm \frac{\pi }{3}$

Vedclass · Answer

(d) ${\cos ^2}	heta - \frac{5}{2}\cos 	heta + 1 = 0$

$ \Rightarrow $ $\cos 	heta = \frac{{(5/2) \pm \sqrt {(25/4) - 4} }}{2} = \frac{{5 \pm 3}}{4}$

Rejecting $(+)$ sign,

$ \Rightarrow $ $\cos 	heta = \frac{1}{2} = \cos \left( {\frac{\pi }{3}} ight) $

$\Rightarrow 	heta = 2n\pi \pm \frac{\pi }{3}$.

If $\cos \theta + \sec \theta = \frac{5}{2}$, then the general value of $\theta $ is

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