If frac{1 - cos 2theta}{1 + cos 2theta} = 3,t | vedclass

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(D) Given the equation: $\frac{1 - \cos 2	heta}{1 + \cos 2	heta} = 3$Using the trigonometric identities $\cos 2	heta = 1 - 2\sin^2 	heta$ and $\co

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$n\pi \pm \frac{\pi}{3}$

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(D) Given the equation: $\frac{1 - \cos 2	heta}{1 + \cos 2	heta} = 3$Using the trigonometric identities $\cos 2	heta = 1 - 2\sin^2 	heta$ and $\cos 2	heta = 2\cos^2 	heta - 1$,we get:$\frac{1 - (1 - 2\sin^2 	heta)}{1 + (2\cos^2 	heta - 1)} = 3$$\frac{2\sin^2 	heta}{2\cos^2 	heta} = 3$$	an^2 	heta = 3$$	an^2 	heta = (\sqrt{3})^2 = 	an^2(\frac{\pi}{3})$The general solution for $	an^2 	heta = 	an^2 \alpha$ is $	heta = n\pi \pm \alpha$.Therefore,$	heta = n\pi \pm \frac{\pi}{3}$.

If $\frac{1 - \cos 2\theta}{1 + \cos 2\theta} = 3$,then the general value of $\theta$ is

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