જો sqrt 3 cos ,theta + sin theta = sqrt 2 , ત | vedclass

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Question

(d) $\frac{{\sqrt 3 }}{2}\cos 	heta + \frac{1}{2}\sin 	heta = \frac{{\sqrt 2 }}{2}$     { dividing by $\sqrt {{{(\sqrt 3 )}^2} + {1^2

Vedclass · Accepted Answer

$n\pi + {( - 1)^n}\frac{\pi }{4} - \frac{\pi }{3}$

Vedclass · Answer

(d) $\frac{{\sqrt 3 }}{2}\cos 	heta + \frac{1}{2}\sin 	heta = \frac{{\sqrt 2 }}{2}$     { dividing by $\sqrt {{{(\sqrt 3 )}^2} + {1^2}} = 2 $}

$ \Rightarrow $ $\sin \left( {	heta + \frac{\pi }{3}} ight) = \frac{1}{{\sqrt 2 }} = \sin \left( {\frac{\pi }{4}} ight)$

$ \Rightarrow $ $	heta = n\pi + {( - 1)^n}\frac{\pi }{4} - \frac{\pi }{3}$.

જો $\sqrt 3 \cos \,\theta + \sin \theta = \sqrt 2 ,$ તો $\theta $ નો વ્યાપક ઉકેલ મેળવો.

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