If 5tan theta = 4, then frac{{5sin theta - 3c | vedclass

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Question

(c) $5	an 	heta = 4 \Rightarrow 	an 	heta = \frac{4}{5}$

$	herefore \sin 	heta = \frac{4}{{\sqrt {41} }}$ and

$\cos 	heta = \frac{5}

Vedclass · Accepted Answer

$1/6$

Vedclass · Answer

(c) $5	an 	heta = 4 \Rightarrow 	an 	heta = \frac{4}{5}$

$	herefore \sin 	heta = \frac{4}{{\sqrt {41} }}$ and

$\cos 	heta = \frac{5}{{\sqrt {41} }}$

$\frac{{5\sin 	heta - 3\cos 	heta }}{{5\sin 	heta + 2\cos 	heta }}$

$= \frac{{5 	imes \frac{4}{{\sqrt {41} }} - 3 	imes \frac{5}{{\sqrt {41} }}}}{{5 	imes \frac{4}{{\sqrt {41} }} + 2 	imes \frac{5}{{\sqrt {41} }}}}$ 

$\frac{{20 - 15}}{{20 + 10}} = \frac{5}{{30}} = \frac{1}{6}$.

If $5\tan \theta = 4,$ then $\frac{{5\sin \theta - 3\cos \theta }}{{5\sin \theta + 2\cos \theta }} = $

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