If $\alpha,-\frac{\pi}{2}<\alpha<\frac{\pi}{2}$ is the solution of $4 \cos \theta+5 \sin \theta=1$, then the value of $\tan \alpha$ is

  • [JEE MAIN 2024]
  • A

    $\frac{10-\sqrt{10}}{6}$

  • B

     $\frac{10-\sqrt{10}}{12}$

  • C

     $\frac{\sqrt{10}-10}{12}$

  • D

    $\frac{\sqrt{10}-10}{6}$

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