If $a_{1}, a_{2}, a_{3}, \ldots$ and $b_{1}, b_{2}, b_{3}, \ldots$ are $A.P.$ and $a_{1}=2, a_{10}=3, a_{1}b_{1}=1=a_{10}b_{10}$,then $a_{4}b_{4}$ is equal to

  • A
    $\frac{35}{27}$
  • B
    $1$
  • C
    $\frac{27}{28}$
  • D
    $\frac{28}{27}$

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