If $A = \{ x:x$ is a natural number $\} ,B = \{ x:x$ is an even natural number $\} $ $C = \{ x:x$ is an odd natural number $\} $ and $D = \{ x:x$ is a prime number $\} ,$ find $B \cap C$
$A = \{ x:x$ is a natural number $\} = \{ 1,2,3,4,5 \ldots \} $
$B = \{ x:x$ is an even natural number $\} = \{ 2,4,6,8 \ldots \} $
$C = \{ x:x$ is an odd natural number $\} = \{ 1,3,5,7,9 \ldots \} $
$D = \{ x:x$ is a primenumber $\} = \{ 2,3,5,7 \ldots \}$
$B \cap C=\varnothing$
If $A$ and $B$ are not disjoint sets, then $n(A \cup B)$ is equal to
Show that if $A \subset B,$ then $(C-B) \subset( C-A)$
Consider the following relations :
$(1) \,\,\,A - B = A - (A \cap B)$
$(2) \,\,\,A = (A \cap B) \cup (A - B)$
$(3) \,\,\,A - (B \cup C) = (A - B) \cup (A - C)$
which of these is/are correct
If $A$ and $B$ are two sets, then $A \cup B = A \cap B$ iff
Let $A = \{ (x,\,y):y = {e^x},\,x \in R\} $, $B = \{ (x,\,y):y = {e^{ - x}},\,x \in R\} .$ Then