If $A$ and $B$ are not disjoint sets,then $n(A \cup B)$ is equal to

  • A
    $n(A) + n(B)$
  • B
    $n(A) + n(B) - n(A \cap B)$
  • C
    $n(A) + n(B) + n(A \cap B)$
  • D
    $n(A) \times n(B)$

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