Let $A = \{ (x,\,y):y = {e^x},\,x \in R\} $, $B = \{ (x,\,y):y = {e^{ - x}},\,x \in R\} .$ Then
$A \cap B = \phi $
$A \cap B \ne \phi $
$A \cup B = {R^2}$
None of these
If $A = \{x : x$ is a multiple of $4\}$ and $B = \{x : x$ is a multiple of $6\}$ then $A \cap B$ consists of all multiples of
Let $A$ and $B$ be sets. If $A \cap X=B \cap X=\phi$ and $A \cup X=B \cup X$ for some set $X ,$ show that $A = B$
( Hints $A = A \cap (A \cup X),B = B \cap (B \cup X)$ and use Distributive law )
State whether each of the following statement is true or false. Justify you answer.
$\{2,3,4,5\}$ and $\{3,6\}$ are disjoint sets.
If $A$ and $B$ are disjoint, then $n(A \cup B)$ is equal to
If $A=\{1,2,3,4\}, B=\{3,4,5,6\}, C=\{5,6,7,8\}$ and $D=\{7,8,9,10\} ;$ find
$B \cup C$