જો $x$ ત્રીજા ચરણમાં હોય અને $\cos x=-\frac{3}{5},$ તો બાકીનાં પાંચ ત્રિકોણમિતિય વિધેયોનાં મૂલ્યો શોધો. 

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since $\cos x=-\frac{3}{5},$ we have sec $x=-\frac{5}{3}$

Now     $\sin ^{2} x+\cos ^{2} x=1, \text { i.e., } \sin ^{2} x=1-\cos ^{2} x $

or   $\sin ^{2} x=1-\frac{9}{25}=\frac{16}{25}$

Hence $\quad \sin x=\pm \frac{4}{5}$

since $x$ lies in third quadrant, $\sin x$ is negative. Therefore

$\sin x=-\frac{4}{5}$

which also gives

${\cos ec}\, x=-\frac{5}{4}$

Further, we have

$\tan x=\frac{\sin x}{\cos x}=\frac{4}{3} \text { and } \cot x=\frac{\cos x}{\sin x}=\frac{3}{4}$

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